Rmo 1993 __full__ May 2026

Second radical: ( x+8-6\sqrtx-1 = (t^2+1)+8 - 6t = t^2 - 6t + 9 = (t-3)^2 ).

First radical: ( x+3-4\sqrtx-1 = (t^2+1)+3 - 4t = t^2 - 4t + 4 = (t-2)^2 ). rmo 1993

( x = t^2 + 1 ), with ( t \in [2,3] ). So ( x \in [5, 10] ). Second radical: ( x+8-6\sqrtx-1 = (t^2+1)+8 - 6t